Geo-Synchronous Orbit

[Kaito]

Okay, so i've managed to Get into orbit with both the DG and Atlantis (Docking at ISS/ going to the moon are still out of the question)

Now, using the Delta Glider, how do i get to a Geo-Synchronous Orbit?

 

[Urwumpe]

Okay, so i've managed to Get into orbit with both the DG and Atlantis (Docking at ISS/ going to the moon are still out of the question)

Now, using the Delta Glider, how do i get to a Geo-Synchronous Orbit?

Just enter a orbit which has exactly 86400 seconds orbit period (T).

 

[Kaito]

Okay, thanks. Would that mean changing my ApA/PeA accordingly, or is there an easier way?

What about an equatorial Geosynchronous orbit?

 

[Urwumpe]

Okay, thanks. Would that mean changing my ApA/PeA accordingly, or is there an easier way?

What about an equatorial Geosynchronous orbit?

Orbit Period is a function of semimajor axis = (Apoapsis + periapsis)/2

Most geostationary satellites are in a circular orbit with radius 42164 km, if I remember correctly.

 

[eveningsky339]

Your APA/PEA will be roughly 20,000 km above the surface. Not an exact measurement, but it's good for starters.

 

[Jarvitä]

Your APA/PEA will be roughly 20,000 km above the surface. Not an exact measurement, but it's good for starters.

Actually, it's closer to 37 000 km.

Just enter an equatorial circular orbit with a radius somewhere around 42164, then increase or decrease it's radius (be sure to maintain a near-zero eccentricity) until the orbital period reaches 1 day.

 

[Zatnikitelman]

A good way to help is to use Surface MFD in the GS mode. You're reaidng your relative speed to the ground. In a perfect Geostationary orbit, the GS should equal 0.

 

[Tachyon]

Gotta love the wiki !

http://en.wikipedia.org/wiki/Geostationary

 

[eveningsky339]

Actually, it's closer to 37 000 km.

Just enter an equatorial circular orbit with a radius somewhere around 42164, then increase or decrease it's radius (be sure to maintain a near-zero eccentricity) until the orbital period reaches 1 day.

Oh. My mistake. :sorry:

 

[n72.75]

Actually, it's closer to 37 000 km.

Just enter an equatorial circular orbit with a radius somewhere around 42164, then increase or decrease it's radius (be sure to maintain a near-zero eccentricity) until the orbital period reaches 1 day.

35,786 KM above surface

 

[mjessick]

A geosynchronous orbit has a period equal to the Earth's "sidereal" rotation period: the time it takes to rotate around its spin axis 360 degrees (86164 seconds).

This is slightly shorter than 24 hours ("mean solar day") which is the mean time it takes to rotate around until it points at the sun again. (Because the Earth is orbiting around the sun, Earth has to rotate more than 360 degrees around its axis each "mean solar day" since Earth has also orbited approximately 1 degree around the sun over the 24 hours. (Draw a diagram.)