Except that it ISN'T 0! That's the mistake in the model! That would mean that the energy just poofs and disappears! And with that, momentum would as well.
Yes, but the program does not know that.
All this program does is solve Maxwell equations inside the em-drive cavity. And the solution is that at one end of the cavity, <S> != 0, while at the other end, <S>=0. We don't want to throw out Maxwell simply because we don't like the result, do we?
If Maxwell holds, then there is a good chance that the Poynting theorem will also hold:
This is where it gets interesting. If <S> is non-zero, then the first term of the equation is also non-zero. But since the equation must balance out to zero, then the energy pumped in via the first term must go out either via the middle terms or via the last term. It cannot be the last term, because this is simply a Lorentz force moving carriers in the direction of the Poynting vector (see textbook solution for the coax cable), but you don't have a conductor in the direction of the Poynting vector, because the cavity wall is perpenticular the Poynting vector!
That leaves the two middle terms which simply describe the energy stored locally in the E and B fields. So what this program tells you is that once you power the device on, it starts building up potentially very large E and B fields near the wide end.
And there is really nothing questionable up to this point. Assuming that the guy has simulated this correctly of course.
So then...
Assume hypothetically that there exists a yet undiscovered electrogravitic effect which manifests at very high densities of e-m fields. Or, to put it differently, assume that E/B and G fields are indeed coupled, but the coupling coefficient is very low -- so low, that the arising force is not observable most of the time.
But, since the device can build up a very strong E/B field at one end, at one point the field becomes strong enough that the electrogravitic effect starts to manifest itself. This explains the behavior seen in
this video, where the force appears only several seconds after the device is powered up: it takes time to build up the field to values at which the EB/G coupling kicks in. Once that happens, the field energy starts being converted into kinetic energy (force).
---------- Post added at 08:17 AM ---------- Previous post was at 08:03 AM ----------
When you emit a photon, the photon pushes you away. When that same photon hits the other wall, it stops you.
Yes! This is why I'm saying that we still have an apparent CoM violation, even if we don't have CoE violation.
That said, observe that the wavelength of the photon is the same as the length of the cavity, so the photon cannot be treated as a particle and it is subject to Heinseberg's uncertainity. Does CoM really hold in such regime?
See also Casimir effect, which also appears to violate CoM: the plates are being pushed together, but where is the reaction mass?
All old backwards traditionalist science meant to keep creative minds down.
