Still I don't get it...
Does anyone know calculus??
The problem with trying to integrate directly to a solution (the lots of calculus way) is that it requires more calculus than I know. I can do calculus in one variable just fine (which is how I got the potential energy of position formula, though I glossed over that bit), and a little multivariable calc, but I think your preferred method requires some sort of more advanced calculus, which I don't know yet.
I'm not sure exactly how to explain my way better, but I'll try to boil it down to just three formulas (each of which builds on the ones before):
velocity_later = square_root(velocity_now^2 - (2 * universal_gravitational_constant * mass_of_planet / distance_from_center_of_planet_now) + (2 * universal_gravitational_constant * mass_of_planet / distance_from_center_of_planet_later))
vertical_velocity_later = square_root(velocity_later^2 - ((distance_from_center_of_planet_now / distance_from_center_of_planet_later)^2 * (velocity_now^2 - vertical_velocity_now^2))
angle = asin(vertical_velocity_later / velocity_later)
"now" is right now, of course, and "later" is at some point in the future of your choosing (the entry interface). Since the only value you have to know ahead of time for "later" is the distance from the center of the planet, you choose this to be the altitude of the entry interface + the radius of the planet. You can look up the universal gravitational constant on Google.
Of course, these are just some formulas (which I think is what you want). If you want to know where they come from, see my previous post, and google whatever terms are unfamiliar.
I hope this helps.
By the way, I made a mistake in my previous post. I'm fixing it now, but if you looked at it before a message appears at the end of it that says it's fixed, don't trust what you find there. I corrected it for this post.
edit: It's interesting to note that the mass of the vessel cancelled out when I combined the formulas above. It makes sense that it should, since the answer shouldn't depend on the mass of the vessel, but it's interesting.