Hammer and Feather does not fall into same time to the moon surface!

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Hi freaks :lol:

I bet that a feather and a hammer does not fall into the same time from the same alt to the moon surface.

Here my crazy consideration:
Of course, if you realease they both at same time, they will touch the ground at same time. But if you drop them single, the hammer will "fall" faster to the suface, arround 1.5e-25 s

The reason:
Because the bigger mass of the hammer, the hammer is attracting the moon more than the feather.

Calculation:

mh = 0.02 kg (mass of the hammer)
mf ~ 0 (mass of the feather)

r = 1738 km (radius of the moon)

g = (G * m) / r² (Gravitational acceleration)

m = 7.349e22 kg (mass of the moon)

m1 = m + 0.02 kg (maas of moon and hammer)
= 73490000000000000000000.02 kg
m2 ~ m (maas of moon "and feather")
= 73490000000000000000000 kg

g1 = (6.67428e-11 * m1) / r²
= 1.6238021997958051329451604806313

g2= (6.67428e-11 * m2) / r²
= 1.6238021997958051329451600387202

t = sqrt(2 / g) (only for fall alt = 1m !!!! )

t1 = sqrt(2/g1) (only for fall alt = 1m; time for hammer)
= 1.1098094924787423979523526752024 s


t2 = sqrt(2/g2) (only for fall alt = 1m; time for feather)
= 1.1098094924787423979523528262174 s

diff ~ 1.5e-25
(much more than the planck time, that's about 10e-43 s)


is this calculation "nearly" correct ?

(lol):rofl:
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You forget one important aspect:

Both hammer and feather are part of the moon until you separate the masses by releasing them from your hand. So you would have to include the effect of you lifting hammer and feather from the moon into 1m height, displacing the CoG of the moon first.

;)
 
You forget one important aspect:

Both hammer and feather are part of the moon until you separate the masses by releasing them from your hand. So you would have to include the effect of you lifting hammer and feather from the moon into 1m height, displacing the CoG of the moon first.

;)

Urwumpe, thats why i said "nealy" ;)
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test

Also hammer will touch the surface earlier simply because it's bigger... so what?
Look this...
Feather & Hammer Drop on Moon


That's why he has droped them at same time.
Apollo was a fake! ;)
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Maybe the hammer hits the ground a 10000000000000000000st part of a second earlier because of the moons very very very thin atmosphere.
 
Its a conspiracy I tell ya'
 
Maybe the hammer hits the ground a 10000000000000000000st part of a second earlier because of the moons very very very thin atmosphere.

How do you have calculate that? It's depents, if the feather is from an african or from an european carrier pigeon. :huh:
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Or if it's the dorsal guiding feather of the unladen African or European Swallow. :P
 
How do you have calculate that? It's depents, if the feather is from an african or from an european carrier pigeon. :huh:

I did not calculate it, I just pressed the 1 an then the 0 for a few seconds :lol::lol:.
 
Or if it's the dorsal guiding feather of the unladen African or European Swallow. :P

Yes, but i don't think that an African or European Swallow can fly to the moon, even without a Coconut, so how they can lose a feather there? :beach:
 
Yes, but i don't think that an African or European Swallow can fly to the moon, even without a Coconut, so how they can lose a feather there? :beach:

Maybe two of them shared the load with a piece of string?

"Oww do youuuu knoooww soo much abbooout Swallowws?"
 
Not to be picky...

Are we referring to the statement that two objects of different masses will fall at the equal speed and reach the ground at the same time if air resistance is neglected, as in a vacuum?

I think that statement was made by Galileo. Long before there was any knowledge of how gravity acts at a distance (inverse square of the radius law).

A specification is in order for the statement: "Under an approximately constant gravitational force proportional to the inertial mass of the objects".

For Newtonian gravity, this condition is recreated on Earth and other planets, by being quite close to a mass that is HUGE in comparison to that of the objects.

Not that I mean to teach anyone about gravitation here. Just pointing out that the statement is about the conditions Galileo experimented with, and that Galileo was just trying to show that Aristotelian physics were dead wrong, as well as demonstrating that gravitational mass equals inertial mass, which is non trivial.
 
Why the atmosphere

I don't think the atmosphere of the moon is enough to change anything about the feather. It's like saying we should take solar neutrinos into account when we measure Earth's orbit around the sun
 
I don't think the atmosphere of the moon is enough to change anything about the feather. It's like saying we should take solar neutrinos into account when we measure Earth's orbit around the sun

We should! Otherwise, after a few billion years, we'll be off by a tiny (but significant!) fraction of an inch! We need absolute precision! :P
 
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