The tricky bit in having a low lunar orbit is dealing with mass concentrations (mascons). As part of Apollo 16, the satellite PFS-2 was put in orbit around the moon to measure charged particles and magnetic fields. This satellite crashed into the moon just 35 days later because lunar gravitational anomalies had perturbed its orbit.
I have been trying to calculate a sun-synchronous lunar orbit at 86° using the excel sheet that user boogabooga posted in this thread. The mean radius of the moon is listed on Wikipedia as 1737.1 km. I don't know enough about Legendre polynomials to calculate the J2 value for the moon, but I did find this value online as 0.0002027. The gravitational constant of the moon I was able to calculate:
(0.0000000000667384*7.3477E+22)/1000000000 = 4903.737417 km^3/s^2
After modifying the parameters of orbited body in the excel sheet, I started playing with the orbital parameters of the satellite to achieve the desired inclination of 86°. I actually ended up with an inclination of 94° as I assumed this should be equivalent. I ended up with an orbital height of 150 km with an eccentricity of 0.85.
Am I doing this right? Is a lunar Sun-synchronous orbit at 86° possible with zero eccentricity?
http://science.nasa.gov/science-news/science-at-nasa/2006/06nov_loworbit/ said:There are actually a number of 'frozen orbits' where a spacecraft can stay in a low lunar orbit indefinitely. They occur at four inclinations: 27º, 50º, 76º, and 86º"—the last one being nearly over the lunar poles.
I have been trying to calculate a sun-synchronous lunar orbit at 86° using the excel sheet that user boogabooga posted in this thread. The mean radius of the moon is listed on Wikipedia as 1737.1 km. I don't know enough about Legendre polynomials to calculate the J2 value for the moon, but I did find this value online as 0.0002027. The gravitational constant of the moon I was able to calculate:
(0.0000000000667384*7.3477E+22)/1000000000 = 4903.737417 km^3/s^2
After modifying the parameters of orbited body in the excel sheet, I started playing with the orbital parameters of the satellite to achieve the desired inclination of 86°. I actually ended up with an inclination of 94° as I assumed this should be equivalent. I ended up with an orbital height of 150 km with an eccentricity of 0.85.
Am I doing this right? Is a lunar Sun-synchronous orbit at 86° possible with zero eccentricity?