Where,
V=DeltaV and is known (you choose a DeltaV you require)
I=Isp and is known (You choose an Isp you like)
f=fuel mass (Solve for this)
m=empty mass (When given this)
For a given DeltaV and Isp you can determine the weight to fuel ratio as follows:
V = I*ln(m/(m+f))
V/I = ln(m/(m+f))
e^(V/I) = m/(m+f)
(m+f)/m = 1/(e^(V/I))
1+f/m = 1/(e^(V/I))
f/m = 1/(e^(V/I)) -1
f = m/(e^(V/I)) - m
alternately, to get m when given f:
f/m = 1/(e^(V/I)) -1
m/f = (e^(V/I)) -1
m = f*(e^(V/I)) - f
I think... try that and see how it goes.
---------- Post added at 08:14 AM ---------- Previous post was at 08:06 AM ----------
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